.5x^2-9x+41=0

Solution for .5x^2-9x+41=0 equation:

Simplifying
0.5x2 + -9x + 41 = 0

Reorder the terms:
41 + -9x + 0.5x2 = 0

Solving
41 + -9x + 0.5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
0.5 the coefficient of the squared term: 

Divide each side by '0.5'.
82 + -18x + x2 = 0

Move the constant term to the right:

Add '-82' to each side of the equation.
82 + -18x + -82 + x2 = 0 + -82

Reorder the terms:
82 + -82 + -18x + x2 = 0 + -82

Combine like terms: 82 + -82 = 0
0 + -18x + x2 = 0 + -82
-18x + x2 = 0 + -82

Combine like terms: 0 + -82 = -82
-18x + x2 = -82

The x term is -18x.  Take half its coefficient (-9).
Square it (81) and add it to both sides.

Add '81' to each side of the equation.
-18x + 81 + x2 = -82 + 81

Reorder the terms:
81 + -18x + x2 = -82 + 81

Combine like terms: -82 + 81 = -1
81 + -18x + x2 = -1

Factor a perfect square on the left side:
(x + -9)(x + -9) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.